- d= distance between the planes
- n = order of refraction
- θ= angel of refraction
- λ = wavelength
Crystal Systems:
- Total number of crystal systems: 7
- Total number of Bravais Lattices: 14
Crystal Systems
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Bravais Lattices
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Intercepts
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Crystal angle
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Example
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Cubic
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Primitive, Face Centered, Body Centered
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a = b = c
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a = b = g = 90o
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Pb,Hg,Ag,Au Diamond, NaCl, ZnS
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Orthorhombic
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Primitive, Face Centered, Body Centered, End Centered
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a ≠ b ≠ c
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a = b = g = 90o
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KNO2, K2SO4
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Tetragonal
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Primitive, Body Centered
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a = b ≠ c
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a = b = g = 90o
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TiO2,SnO2
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Monoclinic
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Primitive, End Centered
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a ≠ b ≠ c
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a = g = 90o, b≠ 90o
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CaSO4,2H2O
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Triclinic
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Primitive
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a ≠ b ≠ c
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a≠b≠g≠900
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K2Cr2O7, CaSO45H2O
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Hexagonal
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Primitive
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a = b ≠ c
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a = b = 900, g = 120o
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Mg, SiO2, Zn, Cd
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Rhombohedra
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Primitive
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a = b = c
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a = g = 90o, b≠ 90o
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As, Sb, Bi, CaCO3
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Number of atoms in unit cells.
Primitive cubic unit cell:
- Number of atoms at corners = 8×1/8 =1
- Number of atoms in faces = 0
- Number of atoms at body-centre: =0
- Total number of atoms = 1
Body-centred cubic unit cell:
- Number of atoms at corners = 8×1/8 =1
- Number of atoms in faces = 0
- Number of atoms at body-centre: =1
- Total number of atoms = 2
Face-centred cubic or cubic-close packed unit cell:
- Number of atoms at corners = 8×1/8 =1
- Number of atoms in faces = 6×1/2 = 3
- Number of atoms at body-centre: = 0
- Total number of atoms = 4
Packing Efficiency
Packing Efficiency = (Volume occupied by all the atoms present in unit cell / Total volume of unit cell)×100
Close structure
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Number of atoms per unit cell ‘z’.
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Relation between edge length ‘a’ and radius of atom ‘r’
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Packing Efficiency
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hcp and ccp or fcc
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4
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r = a/(2√2)
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74%
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bcc
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2
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r = (√3/4)a
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68%
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Simple cubic lattice
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1
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r = a/2
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52.4%
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Density of crystal lattice:
r = (Number of atoms per unit cell × Mass number)/(Volume of unit cell × NA)
or
Octahedral and Tetrahedral Voids:
Number of octahedral voids = Number of effective atoms present in unit cell
Number of tetrahedral voids = 2×Number of effective atoms present in unit cell
So, Number of tetrahedral voids = 2× Number of octahedral voids.
Coordination numbers and radius ratio:
Coordination numbers
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Geometry
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Radius ratio (x)
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Example
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2
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Linear
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x < 0.155
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BeF2
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3
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Planar Triangle
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0.155 ≤ x < 0.225
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AlCl3
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4
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Tetrahedron
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0.225 ≤ x < 0.414
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ZnS
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4
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Square planar
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0.414 ≤ x < 0.732
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PtCl42-
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6
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Octahedron
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0.414 ≤ x < 0.732
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NaCl
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8
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Body centered cubic
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0.732 ≤ x < 0.999
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CsCl
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Classification of Ionic Structures:
Structures
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Descriptions
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Examples
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Rock Salt Structure
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Anion(Cl-) forms fcc units and cation(Na+) occupy octahedral voids. Z=4 Coordination number =6
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NaCl, KCl, LiCl, RbCl
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Zinc Blende Structure
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Anion (S2-) forms fcc units and cation (Zn2+) occupy alternate tetrahedral voids Z=4 Coordination number =4
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ZnS , BeO
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Fluorite Structures
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Cation (Ca2+) forms fcc units and anions (F-) occupy tetrahedral voids Z= 4 Coordination number of anion = 4 Coordination number of cation = 8
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CaF2, UO2, and ThO2
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Anti- Fluorite Structures
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Oxide ions are face centered and metal ions occupy all the tetrahedral voids.
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Na2O, K2O and Rb2O.
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Cesium Halide Structure
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Halide ions are primitive cubic while the metal ion occupies the center of the unit cell.
Z=2
Coordination number of = 8
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All Halides of Cesium.
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Pervoskite Structure
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One of the cation is bivalent and the other is tetravalent. The bivalent ions are present in primitive cubic lattice with oxide ions on the centers of all the six square faces. The tetravalent cation is in the center of the unit cell occupying octahedral void.
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CaTiO3, BaTiO3
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Spinel and Inverse Spinel Structure
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Spinel :M2+M23+O4, where M2+ is present in one-eighth of tetrahedral voids in a FCC lattice of oxide ions and M3+ ions are present in half of the octahedral voids. M2+ is usually Mg, Fe, Co, Ni, Zn and Mn; M3+is generally Al, Fe, Mn, Cr and Rh.
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MgAl2O4 ,ZnAl2O4, Fe3O4,FeCr2O4etc.
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Defects in crystal:
Stoichiometric Defects
1. Schottky Defects
- Some of the lattice points in a crystal are unoccupied.
- Appears in ionic compounds in which anions and cations are of nearly same size.
- Decreases the density of lattice
- Examples: NaCl and KCl
2. Frenkel Defects
- Ion dislocate from its position and occupies an interstitial position between the lattice points
- Appears in crystals in which the negative ions are much larger than the positive ion.
- Does not affect density of the crystal.
- Examples: AgBr, ZnS
Non-Stoichiometric Defects
1. Metal Excess defect:
Metal excess defect occurs due to
- anionic vacancies or
- presence of extra cation.
- F-Centres: hole produced due to absence of anion which is occupied by an electron.
2. Metal deficiency defect:
Metal deficiency defect occurs
- due to variable valency of metals
- when one of the positive ions is missing from its lattice site and the extra negative charge is balanced by some nearby metal ion acquiring two charges instead of one
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